Centripetal Force Lab Activity

Centripetal Force Lab act Analysis 1. A) Average Percent Difference 50g ( harbors express in newtons) tint 1 wait the amount out pass judgment of the ii variables Average nourish= revalue 1+ place 2 /2 = 0. 49+ 0. 61/2 = 1. 1/2 = 0. 55 note 2 purpose the conflict betwixt the ii variables Difference= Value 2- Value 1 = Fc- Fg = 0. 61- 0. 49 = 0. 12 Step 3 project % struggle % leaving= difference of the variables / average of the variables x 100 = 0. 12/ 0. 55 x 100 = 21. 81% 100g (values expressed in newtons)Step 1 Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 0. 98+ 1. 84/2 = 2. 82/2 = 1. 41 Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 1. 84- 0. 98 = 0. 86 Step 3 Calculate % difference % difference= difference of the variables / average of the variables x 100 = 0. 86/ 1. 41 x 100 = 60. 99% 150g (values expressed in newtons) Step 1 Calculate the average value of the two vari ables Average Value= Value 1+ Value 2 /2 = 1. 47+ 2. 19/2 = 3. 66/2 = 1. 83Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 2. 19- 1. 47 = 0. 72 Step 3 Calculate % difference % difference= difference of the variables / average of the variables x 100 = 0. 72/ 1. 83 x 100 = 39. 34% 200g (values expressed in newtons) Step 1 Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 1. 96+ 2. 66/2 = 4. 62/2 = 2. 31 Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 2. 66- 1. 96 = 0. 70 Step 3 Calculate % difference difference= difference of the variables / average of the variables x 100 = 0. 70/2. 31 x 100 = 30. 30% 250g (values expressed in newtons) Step 1 Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 2. 45+ 3. 57/2 = 6. 02/2 = 3. 01 Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 3. 57- 2. 45 = 1. 12 Step 3 Calculate % difference % difference= difference of the variables / average of the variables x 100 = 1. 12/ 3. 01 x 100 = 37. 20% Average % difference = Sum of all 5 averages/5 21. 81+ 60. 99+ 39. 34+ 30. 30+ 37. 20/ 5 = 189. 64/ 5 = 37. 92% B) cant Calculations (Graph is displayed on a pitchfork sheet) 50g Slope= Rise/ candidacy = 0. 61/0. 49 = 1. 25 100g Slope= Rise/Run = 1. 84/0. 98 = 1. 877 150g Slope= Rise/Run = 2. 19/1. 47 = 1. 489 200g Slope= Rise/Run = 2. 66/1. 96 = 1. 357 250g Slope= Rise/Run = 3. 57/2. 45 = 1. 457 After work out the side of meat of each section of the graph (each section corresponds to a received pot used in the laboratory activity) it is unambiguous that it varies from its expect value by a great amount.The expected value of the slope was 1 as the rise and the run were supposed to be equal. notwithstanding in our quality the rise and the run varied greatly and then because they were different numbers the slope di d not turn out to be 1 (the only way to get a slope of 1 is if both the numerator and denominator are equal, as a number divided by itself is always 1 and a number divided by a different number can never equal 1). 2. Yes the data self-collected did verify the equation Fc=42Rmf2. This is because the only varying value in this discipline f, had a direct relationship with the value of Fc.The only new(prenominal) values that had to be determined in this lab was the radius and the mass of the caoutchouc plug but they were constant variables (constant at 0. 87m and 12. 4g respectively) meaning that they had no varying effect on the value of Fc. For in that location to be a relationship between Fc and 42Rmf2 when the value of any of the variables changes the value of Fc has to change as well Because the value of f had a direct relationship with the value of Fc, when the value of f changed the value of Fc changed as well. In this particular case when the value of f grew so did the v alue of Fc.For example, during the 50g bear witness the frequency was 1. 2Hz and the Fc was 0. 61N, and during the 100g test the frequency was 2. 08Hz and the Fc was 1. 84N. This shows that as the frequency increases so does the Fc acting on the administration. This and then shows the relationship between Fc and 42Rmf2. 3. A) When the string was pulled down and the stopper was still spinning, the stopper started spinning at a faster rate (took less quantify to complete 1 cycle around the trip) B) This happens simply because the radius is cosmos shortened.Because the stopper on the end of the string is moving around the even plenty at a constant speed it is then existence acted upon by a constant net- campaign. In this case the net-force acting upon it (the stopper) is Fc, therefore because it is Fc acting upon it, the force can be calculated by the conventionality 42Rmf2 as that is equal to Fc. In this case because the string with the stopper on the end was being pulled do wn this means that the radius of the entire circle was decreasing (less string= little distance= smaller radius).In that formula if the radius is smaller that means that the centripetal force will be larger. In this case that larger the centripetal force acting on the rubber stopper, the faster the rubber stopper rotates around the horizontal circle. C) The laws of conservation of cleverness state that the total faculty in the system stays the self comparable(prenominal) but simply takes on different forms (energizing and probable being examples). consequently this case is not contrary to the laws of conservation of expertness simply because when the radius is decreasing the rubber stopper speeds up.In the laws of conservation of energy when an purpose is stop number up the object is gaining kinetic energy. However in this case while the stopper is speeding up the hanging mass (along with some of the string) is locomote to the ground. From a conservation of energy perspec tive when an object loses height it loses potential energy. Therefore in this case the object at the top gains kinetic energy while the mass loses potential energy. Because of this energy transfer no energy is lost in the system as hen the object is losing potential energy the other object in the same system is gaining kinetic energy, therefore the energy stays the same. D) In figure skate the skaters do the exact same thing as what was d one(a) in this lab experiment. In order to spin faster they bend natural depression (get mortified to the ground) and knit their arms and legs in. This causes them to spin much faster than they were primarily spinning and follows the same principles that the rubber stopper experiment followed. When they get low they lose potential energy but getting low causes them to tuck in (tuck in their legs and arms) and ultimately have a smaller radius.This smaller radius causes them to have a much greater centripetal force and ultimately causes them to s pin faster and causes them to gain kinetic energy. This follows the laws of conservation of energy as when they lose potential energy they gain kinetic energy (theoretically no energy lost- only transferred) Sources of Error In this particular lab activity there were not very more an(prenominal) potential sources of faulting simply because it was not as complicated an activity as many others. Therefore all errors that were made were simply human measurement errors.The important source of error in this lab activity was measuring the stop consonant/frequency. This was a challenge simply because the individual measuring had to do many different things in a very small amount of time. That one person was responsible for firstly choosing a spot along the travel plan of the horizontal circle to begin the measurement from, then that same person had to start the watch during the very small time frame in which the rubber stopper passed by that specific shoot on the circle. From there the person had to count the stopper pass by 5 generation and stop the watch when it passed by the 5th time.This made it very tough to get a completely accurate measurement for the period and the frequency, as it was very difficult to get an exact measurement of that time period. These slight miscalculations of the frequency caused the calculation of the centripetal force to be slightly defile as well because the calculation of centripetal force depended on the frequency. This is evident because our Fg and Fc calculations are way off, as they were supposed to be nearly the same number as Fg= Fc. X-axis= Fc Y-axis= Fg point 1= 50g point 2= 100g point 3= 150g point 4= 200g point 5= 250g Data masses of stopper 12. 4g Radius of Rotation 87cm Mass of suspended masses cartridge holder for 5 cycles Period (T) Frequency (f) FgFg=mhg FcFc=42Rmf2 50g 4. 2s 0. 84 1. 2Hz 0. 49N 0. 61N 100g 2. 44s 0. 48 2. 08Hz 0. 98N 1. 84N 150g 2. 23s 0. 44 2. 27Hz 1. 47N 2. 19N 200g 1. 99s 0. 4 2. 5Hz 1. 96N 2. 66N 250g 1. 65s 0. 34 2. 9Hz 2. 45N 3. 57N